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⚙️ Option Pattern в Go: гибкая и читаемая настройка объектов

В статье Leapcell ["Option Pattern in Go: Advanced Parameter Handling"](https://dev.to/leapcell/option-pattern-in-go-advanced-parameter-handling-15hf) рассматривается эффективный способ управления параметрами функций и конструкторов в Go.:contentReference[oaicite:7]{index=7}

## 🧩 Проблема

:contentReference[oaicite:9]{index=9}:contentReference[oaicite:11]{index=11}


func NewServer(addr string, port int, timeout time.Duration, maxConn int, protocol string) *Server {
// ...
}


Недостатки:
- :contentReference[oaicite:13]{index=13}
- :contentReference[oaicite:16]{index=16}
- :contentReference[oaicite:19]{index=19}
- :contentReference[oaicite:22]{index=22}:contentReference[oaicite:24]{index=24}

## 💡 Решение: Option Pattern

:contentReference[oaicite:26]{index=26}:contentReference[oaicite:28]{index=28}


type Server struct {
addr string
port int
timeout time.Duration
maxConn int
protocol string
}

type Option func(*Server)

func WithTimeout(t time.Duration) Option {
return func(s *Server) {
s.timeout = t
}
}

func WithMaxConn(max int) Option {
return func(s *Server) {
s.maxConn = max
}
}



:contentReference[oaicite:30]{index=30}:contentReference[oaicite:32]{index=32}


func NewServer(addr string, opts ...Option) *Server {
s := &Server{
addr: addr,
port: 8080,
timeout: 30 * time.Second,
maxConn: 100,
protocol: "tcp",
}

for _, opt := range opts {
opt(s)
}
return s
}


Использование:


server := NewServer("localhost",
WithTimeout(60*time.Second),
WithMaxConn(500),
)


## 🛠️ Дополнительные возможности

- Валидация параметров:


func WithPort(port int) Option {
return func(s *Server) {
if port < 0 || port > 65535 {
panic("invalid port number")
}
s.port = port
}
}


- Группировка опций:


type NetworkOptions struct {
Protocol string
Timeout time.Duration
}

func WithNetworkOptions(opts NetworkOptions) Option {
return func(s *Server) {
s.protocol = opts.Protocol
s.timeout = opts.Timeout
}
}


Преимущества

- :contentReference[oaicite:34]{index=34}
- :contentReference[oaicite:37]{index=37}
- :contentReference[oaicite:40]{index=40}
- :contentReference[oaicite:43]{index=43}:contentReference[oaicite:45]{index=45}

:contentReference[oaicite:47]{index=47}:contentReference[oaicite:49]{index=49}

📌 Читать



tg-me.com/golang_interview/1192
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⚙️ Option Pattern в Go: гибкая и читаемая настройка объектов

В статье Leapcell ["Option Pattern in Go: Advanced Parameter Handling"](https://dev.to/leapcell/option-pattern-in-go-advanced-parameter-handling-15hf) рассматривается эффективный способ управления параметрами функций и конструкторов в Go.:contentReference[oaicite:7]{index=7}

## 🧩 Проблема

:contentReference[oaicite:9]{index=9}:contentReference[oaicite:11]{index=11}


func NewServer(addr string, port int, timeout time.Duration, maxConn int, protocol string) *Server {
// ...
}


Недостатки:
- :contentReference[oaicite:13]{index=13}
- :contentReference[oaicite:16]{index=16}
- :contentReference[oaicite:19]{index=19}
- :contentReference[oaicite:22]{index=22}:contentReference[oaicite:24]{index=24}

## 💡 Решение: Option Pattern

:contentReference[oaicite:26]{index=26}:contentReference[oaicite:28]{index=28}


type Server struct {
addr string
port int
timeout time.Duration
maxConn int
protocol string
}

type Option func(*Server)

func WithTimeout(t time.Duration) Option {
return func(s *Server) {
s.timeout = t
}
}

func WithMaxConn(max int) Option {
return func(s *Server) {
s.maxConn = max
}
}



:contentReference[oaicite:30]{index=30}:contentReference[oaicite:32]{index=32}


func NewServer(addr string, opts ...Option) *Server {
s := &Server{
addr: addr,
port: 8080,
timeout: 30 * time.Second,
maxConn: 100,
protocol: "tcp",
}

for _, opt := range opts {
opt(s)
}
return s
}


Использование:


server := NewServer("localhost",
WithTimeout(60*time.Second),
WithMaxConn(500),
)


## 🛠️ Дополнительные возможности

- Валидация параметров:


func WithPort(port int) Option {
return func(s *Server) {
if port < 0 || port > 65535 {
panic("invalid port number")
}
s.port = port
}
}


- Группировка опций:


type NetworkOptions struct {
Protocol string
Timeout time.Duration
}

func WithNetworkOptions(opts NetworkOptions) Option {
return func(s *Server) {
s.protocol = opts.Protocol
s.timeout = opts.Timeout
}
}


Преимущества

- :contentReference[oaicite:34]{index=34}
- :contentReference[oaicite:37]{index=37}
- :contentReference[oaicite:40]{index=40}
- :contentReference[oaicite:43]{index=43}:contentReference[oaicite:45]{index=45}

:contentReference[oaicite:47]{index=47}:contentReference[oaicite:49]{index=49}

📌 Читать

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Spiking bond yields driving sharp losses in tech stocks

A spike in interest rates since the start of the year has accelerated a rotation out of high-growth technology stocks and into value stocks poised to benefit from a reopening of the economy. The Nasdaq has fallen more than 10% over the past month as the Dow has soared to record highs, with a spike in the 10-year US Treasury yield acting as the main catalyst. It recently surged to a cycle high of more than 1.60% after starting the year below 1%. But according to Jim Paulsen, the Leuthold Group's chief investment strategist, rising interest rates do not represent a long-term threat to the stock market. Paulsen expects the 10-year yield to cross 2% by the end of the year. A spike in interest rates and its impact on the stock market depends on the economic backdrop, according to Paulsen. Rising interest rates amid a strengthening economy "may prove no challenge at all for stocks," Paulsen said.

That growth environment will include rising inflation and interest rates. Those upward shifts naturally accompany healthy growth periods as the demand for resources, products and services rise. Importantly, the Federal Reserve has laid out the rationale for not interfering with that natural growth transition.It's not exactly a fad, but there is a widespread willingness to pay up for a growth story. Classic fundamental analysis takes a back seat. Even negative earnings are ignored. In fact, positive earnings seem to be a limiting measure, producing the question, "Is that all you've got?" The preference is a vision of untold riches when the exciting story plays out as expected.

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